9n^2=6n=3

Solution for 9n^2=6n=3 equation:

9n^2=6n=3

We move all terms to the left:

9n^2-(6n)=0

a = 9; b = -6; c = 0;
Δ = b2-4ac
Δ = -62-4·9·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-6}{2*9}=\frac{0}{18}
=0
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+6}{2*9}=\frac{12}{18}
=2/3
$